Base | Representation |
---|---|
bin | 1001011100010111101… |
… | …1001011010000101001 |
3 | 120111202101200010221111 |
4 | 2113011323023100221 |
5 | 10124224002222441 |
6 | 202310210310321 |
7 | 14502214524043 |
oct | 2270573132051 |
9 | 514671603844 |
10 | 162234414121 |
11 | 628921085aa |
12 | 27537b883a1 |
13 | 123b615a460 |
14 | 7bd058ca93 |
15 | 4347c06081 |
hex | 25c5ecb429 |
162234414121 has 4 divisors (see below), whose sum is σ = 174713984452. Its totient is φ = 149754843792.
The previous prime is 162234414119. The next prime is 162234414131. The reversal of 162234414121 is 121414432261.
It is a happy number.
162234414121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 40576462096 + 121657952025 = 201436^2 + 348795^2 .
It is a cyclic number.
It is not a de Polignac number, because 162234414121 - 21 = 162234414119 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (162234414131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6239785146 + ... + 6239785171.
It is an arithmetic number, because the mean of its divisors is an integer number (43678496113).
Almost surely, 2162234414121 is an apocalyptic number.
It is an amenable number.
162234414121 is a deficient number, since it is larger than the sum of its proper divisors (12479570331).
162234414121 is a wasteful number, since it uses less digits than its factorization.
162234414121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12479570330.
The product of its digits is 9216, while the sum is 31.
Adding to 162234414121 its reverse (121414432261), we get a palindrome (283648846382).
It can be divided in two parts, 16223 and 4414121, that added together give a palindrome (4430344).
The spelling of 162234414121 in words is "one hundred sixty-two billion, two hundred thirty-four million, four hundred fourteen thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •