Base | Representation |
---|---|
bin | 100101001011010000001100… |
… | …011101101110111101001111 |
3 | 210102220112201111022000002102 |
4 | 211023100030131232331033 |
5 | 132412300044140121411 |
6 | 1335423200014545315 |
7 | 46303362540410543 |
oct | 4513201435567517 |
9 | 712815644260072 |
10 | 163501024145231 |
11 | 48107438737973 |
12 | 1640771620823b |
13 | 70301078b4396 |
14 | 2c536c5699a23 |
15 | 13d8084599d3b |
hex | 94b40c76ef4f |
163501024145231 has 2 divisors, whose sum is σ = 163501024145232. Its totient is φ = 163501024145230.
The previous prime is 163501024145131. The next prime is 163501024145233. The reversal of 163501024145231 is 132541420105361.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-163501024145231 is a prime.
It is a super-2 number, since 2×1635010241452312 (a number of 29 digits) contains 22 as substring.
Together with 163501024145233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (163501024145233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81750512072615 + 81750512072616.
It is an arithmetic number, because the mean of its divisors is an integer number (81750512072616).
Almost surely, 2163501024145231 is an apocalyptic number.
163501024145231 is a deficient number, since it is larger than the sum of its proper divisors (1).
163501024145231 is an equidigital number, since it uses as much as digits as its factorization.
163501024145231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 163501024145231 in words is "one hundred sixty-three trillion, five hundred one billion, twenty-four million, one hundred forty-five thousand, two hundred thirty-one".
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