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163659054407 is a prime number
BaseRepresentation
bin1001100001101011010…
…1101111110101000111
3120122102200101101000112
42120122311233311013
510140133204220112
6203103421303235
714552424003212
oct2303265576507
9518380341015
10163659054407
11634532a6972
1227875104b1b
1312582355484
147cc7876779
1543ccd16a22
hex261ad6fd47

163659054407 has 2 divisors, whose sum is σ = 163659054408. Its totient is φ = 163659054406.

The previous prime is 163659054287. The next prime is 163659054409. The reversal of 163659054407 is 704450956361.

It is a strong prime.

It is an emirp because it is prime and its reverse (704450956361) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 163659054407 - 218 = 163658792263 is a prime.

It is a super-2 number, since 2×1636590544072 (a number of 23 digits) contains 22 as substring.

Together with 163659054409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (163659054409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81829527203 + 81829527204.

It is an arithmetic number, because the mean of its divisors is an integer number (81829527204).

Almost surely, 2163659054407 is an apocalyptic number.

163659054407 is a deficient number, since it is larger than the sum of its proper divisors (1).

163659054407 is an equidigital number, since it uses as much as digits as its factorization.

163659054407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2721600, while the sum is 50.

The spelling of 163659054407 in words is "one hundred sixty-three billion, six hundred fifty-nine million, fifty-four thousand, four hundred seven".