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164034133 is a prime number
BaseRepresentation
bin10011100011011…
…11011001010101
3102102122210112021
421301233121111
5313443043013
624135453141
74031160424
oct1161573125
9372583467
10164034133
11846582aa
1246b271b1
1327ca3a23
1417add2bb
15e602a8d
hex9c6f655

164034133 has 2 divisors, whose sum is σ = 164034134. Its totient is φ = 164034132.

The previous prime is 164034127. The next prime is 164034181. The reversal of 164034133 is 331430461.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 164019249 + 14884 = 12807^2 + 122^2 .

It is an emirp because it is prime and its reverse (331430461) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-164034133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 164034098 and 164034107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (164034833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82017066 + 82017067.

It is an arithmetic number, because the mean of its divisors is an integer number (82017067).

Almost surely, 2164034133 is an apocalyptic number.

It is an amenable number.

164034133 is a deficient number, since it is larger than the sum of its proper divisors (1).

164034133 is an equidigital number, since it uses as much as digits as its factorization.

164034133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

The square root of 164034133 is about 12807.5810752851. The cubic root of 164034133 is about 547.4083392212.

Adding to 164034133 its reverse (331430461), we get a palindrome (495464594).

The spelling of 164034133 in words is "one hundred sixty-four million, thirty-four thousand, one hundred thirty-three".