Base | Representation |
---|---|
bin | 11110100011100010… |
… | …00110110111100111 |
3 | 1120100020102101002201 |
4 | 33101301012313213 |
5 | 232043434310343 |
6 | 11311435115331 |
7 | 1120340340346 |
oct | 172161066747 |
9 | 46306371081 |
10 | 16404213223 |
11 | 6a58829212 |
12 | 32198a2b47 |
13 | 1715741458 |
14 | b18911b5d |
15 | 66023c94d |
hex | 3d1c46de7 |
16404213223 has 16 divisors (see below), whose sum is σ = 17455673664. Its totient is φ = 15362529280.
The previous prime is 16404213193. The next prime is 16404213229. The reversal of 16404213223 is 32231240461.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 16404213223 - 217 = 16404082151 is a prime.
It is a super-3 number, since 3×164042132233 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16404213191 and 16404213200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16404213229) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4091886 + ... + 4095892.
It is an arithmetic number, because the mean of its divisors is an integer number (1090979604).
Almost surely, 216404213223 is an apocalyptic number.
16404213223 is a deficient number, since it is larger than the sum of its proper divisors (1051460441).
16404213223 is a wasteful number, since it uses less digits than its factorization.
16404213223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5162.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 16404213223 its reverse (32231240461), we get a palindrome (48635453684).
The spelling of 16404213223 in words is "sixteen billion, four hundred four million, two hundred thirteen thousand, two hundred twenty-three".
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