Base | Representation |
---|---|
bin | 1110111011000100100110… |
… | …1010111100100110011011 |
3 | 2011002120221111120110222111 |
4 | 3232301021222330212123 |
5 | 4122312101313101010 |
6 | 54521423005133151 |
7 | 3312303544605361 |
oct | 356611152744633 |
9 | 64076844513874 |
10 | 16408011065755 |
11 | 5256664544071 |
12 | 1a0bb9585a1b7 |
13 | 92036574243a |
14 | 40a21b029631 |
15 | 1d6c23c5858a |
hex | eec49abc99b |
16408011065755 has 48 divisors (see below), whose sum is σ = 21223184777280. Its totient is φ = 12173006182400.
The previous prime is 16408011065749. The next prime is 16408011065851. The reversal of 16408011065755 is 55756011080461.
It is not a de Polignac number, because 16408011065755 - 25 = 16408011065723 is a prime.
It is a super-3 number, since 3×164080110657553 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16408011065699 and 16408011065708.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 175288065 + ... + 175381645.
It is an arithmetic number, because the mean of its divisors is an integer number (442149682860).
Almost surely, 216408011065755 is an apocalyptic number.
16408011065755 is a deficient number, since it is larger than the sum of its proper divisors (4815173711525).
16408011065755 is a wasteful number, since it uses less digits than its factorization.
16408011065755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95400 (or 95383 counting only the distinct ones).
The product of its (nonzero) digits is 1008000, while the sum is 49.
The spelling of 16408011065755 in words is "sixteen trillion, four hundred eight billion, eleven million, sixty-five thousand, seven hundred fifty-five".
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