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1642256113 is a prime number
BaseRepresentation
bin110000111100010…
…1101011011110001
311020110012020212111
41201320231123301
511330404143423
6430543125321
755460642461
oct14170553361
94213166774
101642256113
11773013363
12399ba3841
1320230c4a4
14118173ba1
159929960d
hex61e2d6f1

1642256113 has 2 divisors, whose sum is σ = 1642256114. Its totient is φ = 1642256112.

The previous prime is 1642256101. The next prime is 1642256131. The reversal of 1642256113 is 3116522461.

It is a happy number.

Together with next prime (1642256131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1558038784 + 84217329 = 39472^2 + 9177^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1642256113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1642356113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 821128056 + 821128057.

It is an arithmetic number, because the mean of its divisors is an integer number (821128057).

Almost surely, 21642256113 is an apocalyptic number.

It is an amenable number.

1642256113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1642256113 is an equidigital number, since it uses as much as digits as its factorization.

1642256113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8640, while the sum is 31.

The square root of 1642256113 is about 40524.7592590012. The cubic root of 1642256113 is about 1179.8142274337.

Adding to 1642256113 its reverse (3116522461), we get a palindrome (4758778574).

The spelling of 1642256113 in words is "one billion, six hundred forty-two million, two hundred fifty-six thousand, one hundred thirteen".