Base | Representation |
---|---|
bin | 1110111100011010110100… |
… | …0100010110100010001111 |
3 | 2011011210200100011021110112 |
4 | 3233012231010112202033 |
5 | 4123202000244201242 |
6 | 54540211232030235 |
7 | 3314053205242061 |
oct | 357065504264217 |
9 | 64153610137415 |
10 | 16431153506447 |
11 | 526545a882309 |
12 | 1a1457409237b |
13 | 9225b3184824 |
14 | 40b3b47d5731 |
15 | 1d762a802c82 |
hex | ef1ad11688f |
16431153506447 has 2 divisors, whose sum is σ = 16431153506448. Its totient is φ = 16431153506446.
The previous prime is 16431153506407. The next prime is 16431153506459. The reversal of 16431153506447 is 74460535113461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16431153506447 - 28 = 16431153506191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16431153506395 and 16431153506404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16431153506407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8215576753223 + 8215576753224.
It is an arithmetic number, because the mean of its divisors is an integer number (8215576753224).
Almost surely, 216431153506447 is an apocalyptic number.
16431153506447 is a deficient number, since it is larger than the sum of its proper divisors (1).
16431153506447 is an equidigital number, since it uses as much as digits as its factorization.
16431153506447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3628800, while the sum is 50.
The spelling of 16431153506447 in words is "sixteen trillion, four hundred thirty-one billion, one hundred fifty-three million, five hundred six thousand, four hundred forty-seven".
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