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16432313411 is a prime number
BaseRepresentation
bin11110100110111000…
…10011010001000011
31120102012022000022102
433103130103101003
5232123133012121
611314321301015
71121131234163
oct172334232103
946365260272
1016432313411
116a72681308
12322719476b
13171b4cc797
14b1c5485a3
1566293d90b
hex3d3713443

16432313411 has 2 divisors, whose sum is σ = 16432313412. Its totient is φ = 16432313410.

The previous prime is 16432313363. The next prime is 16432313431. The reversal of 16432313411 is 11431323461.

It is a happy number.

16432313411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11431323461) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16432313411 - 222 = 16428119107 is a prime.

It is a super-4 number, since 4×164323134114 (a number of 42 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (16432313431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8216156705 + 8216156706.

It is an arithmetic number, because the mean of its divisors is an integer number (8216156706).

Almost surely, 216432313411 is an apocalyptic number.

16432313411 is a deficient number, since it is larger than the sum of its proper divisors (1).

16432313411 is an equidigital number, since it uses as much as digits as its factorization.

16432313411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 29.

Adding to 16432313411 its reverse (11431323461), we get a palindrome (27863636872).

The spelling of 16432313411 in words is "sixteen billion, four hundred thirty-two million, three hundred thirteen thousand, four hundred eleven".