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16432517630513 is a prime number
BaseRepresentation
bin1110111100011111111001…
…1000000100101000110001
32011011221012101222221220002
43233013332120010220301
54123212244003134023
654540554441555345
73314132051144135
oct357077630045061
964157171887802
1016432517630513
115265a9a897976
121a14894aa5b55
1392276c98192a
1440b4a3a493c5
151d76aa45cb28
hexef1fe604a31

16432517630513 has 2 divisors, whose sum is σ = 16432517630514. Its totient is φ = 16432517630512.

The previous prime is 16432517630489. The next prime is 16432517630537. The reversal of 16432517630513 is 31503671523461.

It is a balanced prime because it is at equal distance from previous prime (16432517630489) and next prime (16432517630537).

It can be written as a sum of positive squares in only one way, i.e., 9947514145024 + 6485003485489 = 3153968^2 + 2546567^2 .

It is a cyclic number.

It is not a de Polignac number, because 16432517630513 - 212 = 16432517626417 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (16432513630513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8216258815256 + 8216258815257.

It is an arithmetic number, because the mean of its divisors is an integer number (8216258815257).

Almost surely, 216432517630513 is an apocalyptic number.

It is an amenable number.

16432517630513 is a deficient number, since it is larger than the sum of its proper divisors (1).

16432517630513 is an equidigital number, since it uses as much as digits as its factorization.

16432517630513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 47.

The spelling of 16432517630513 in words is "sixteen trillion, four hundred thirty-two billion, five hundred seventeen million, six hundred thirty thousand, five hundred thirteen".