Base | Representation |
---|---|
bin | 1110111100100010111000… |
… | …1111000010111000110111 |
3 | 2011012000021100212112101021 |
4 | 3233020232033002320313 |
5 | 4123220420031223143 |
6 | 54541210243442011 |
7 | 3314161001053621 |
oct | 357105617027067 |
9 | 64160240775337 |
10 | 16433320570423 |
11 | 5266372056579 |
12 | 1a14a79986307 |
13 | 92286a1239c3 |
14 | 40b53c53bc11 |
15 | 1d7705bb5ced |
hex | ef22e3c2e37 |
16433320570423 has 2 divisors, whose sum is σ = 16433320570424. Its totient is φ = 16433320570422.
The previous prime is 16433320570421. The next prime is 16433320570507. The reversal of 16433320570423 is 32407502333461.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16433320570423 - 21 = 16433320570421 is a prime.
Together with 16433320570421, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 16433320570423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16433320570421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8216660285211 + 8216660285212.
It is an arithmetic number, because the mean of its divisors is an integer number (8216660285212).
Almost surely, 216433320570423 is an apocalyptic number.
16433320570423 is a deficient number, since it is larger than the sum of its proper divisors (1).
16433320570423 is an equidigital number, since it uses as much as digits as its factorization.
16433320570423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 43.
The spelling of 16433320570423 in words is "sixteen trillion, four hundred thirty-three billion, three hundred twenty million, five hundred seventy thousand, four hundred twenty-three".
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