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164335201203 = 3136140248641
BaseRepresentation
bin1001100100001100100…
…1000010101110110011
3120201011210200012001110
42121003021002232303
510143024302414303
6203254453404403
714605244106525
oct2310311025663
9521153605043
10164335201203
116376aa33a78
1227a23639703
131265c462634
147d4d5a1a15
15441c376703
hex2643242bb3

164335201203 has 8 divisors (see below), whose sum is σ = 219274601616. Its totient is φ = 109476300800.

The previous prime is 164335201201. The next prime is 164335201211. The reversal of 164335201203 is 302102533461.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 164335201203 - 21 = 164335201201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (164335201201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20120238 + ... + 20128403.

It is an arithmetic number, because the mean of its divisors is an integer number (27409325202).

Almost surely, 2164335201203 is an apocalyptic number.

164335201203 is a deficient number, since it is larger than the sum of its proper divisors (54939400413).

164335201203 is a wasteful number, since it uses less digits than its factorization.

164335201203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40250005.

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 164335201203 its reverse (302102533461), we get a palindrome (466437734664).

The spelling of 164335201203 in words is "one hundred sixty-four billion, three hundred thirty-five million, two hundred one thousand, two hundred three".

Divisors: 1 3 1361 4083 40248641 120745923 54778400401 164335201203