Base | Representation |
---|---|
bin | 100101010111100010110001… |
… | …011100000010100000000111 |
3 | 210112220021201211011211021012 |
4 | 211113202301130002200013 |
5 | 133020114300004003110 |
6 | 1341311155013112435 |
7 | 46421402211633242 |
oct | 4527426134024007 |
9 | 715807654154235 |
10 | 164345605531655 |
11 | 48402641929079 |
12 | 1652334292871b |
13 | 7091954b14242 |
14 | 2c82526842259 |
15 | 140001668b905 |
hex | 9578b1702807 |
164345605531655 has 4 divisors (see below), whose sum is σ = 197214726637992. Its totient is φ = 131476484425320.
The previous prime is 164345605531567. The next prime is 164345605531663. The reversal of 164345605531655 is 556135506543461.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 164345605531655 - 28 = 164345605531399 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 164345605531594 and 164345605531603.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16434560553161 + ... + 16434560553170.
It is an arithmetic number, because the mean of its divisors is an integer number (49303681659498).
Almost surely, 2164345605531655 is an apocalyptic number.
164345605531655 is a deficient number, since it is larger than the sum of its proper divisors (32869121106337).
164345605531655 is an equidigital number, since it uses as much as digits as its factorization.
164345605531655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32869121106336.
The product of its (nonzero) digits is 97200000, while the sum is 59.
The spelling of 164345605531655 in words is "one hundred sixty-four trillion, three hundred forty-five billion, six hundred five million, five hundred thirty-one thousand, six hundred fifty-five".
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