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16440220013302 = 28220110006651
BaseRepresentation
bin1110111100111100100101…
…1110010101001011110110
32011012200002012101112201201
43233033021132111023312
54123324032310411202
654544311030443114
73314523656260501
oct357171136251366
964180065345651
1016440220013302
115269292669088
121a1628450349a
139233c964c697
1440b9d49a0138
151d79ab76a387
hexef3c97952f6

16440220013302 has 4 divisors (see below), whose sum is σ = 24660330019956. Its totient is φ = 8220110006650.

The previous prime is 16440220013297. The next prime is 16440220013353. The reversal of 16440220013302 is 20331002204461.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×164402200133023 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4110055003324 + ... + 4110055003327.

It is an arithmetic number, because the mean of its divisors is an integer number (6165082504989).

Almost surely, 216440220013302 is an apocalyptic number.

16440220013302 is a deficient number, since it is larger than the sum of its proper divisors (8220110006654).

16440220013302 is an equidigital number, since it uses as much as digits as its factorization.

16440220013302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8220110006653.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 16440220013302 its reverse (20331002204461), we get a palindrome (36771222217763).

The spelling of 16440220013302 in words is "sixteen trillion, four hundred forty billion, two hundred twenty million, thirteen thousand, three hundred two".

Divisors: 1 2 8220110006651 16440220013302