Base | Representation |
---|---|
bin | 11110100111110111… |
… | …01010110001000101 |
3 | 1120102202202202202200 |
4 | 33103323222301011 |
5 | 232132234124013 |
6 | 11315213425113 |
7 | 1121261152140 |
oct | 172373526105 |
9 | 46382682680 |
10 | 16440536133 |
11 | 6a7728814a |
12 | 3229a9b199 |
13 | 172011b3b8 |
14 | b1d689057 |
15 | 663514e73 |
hex | 3d3eeac45 |
16440536133 has 12 divisors (see below), whose sum is σ = 27139932768. Its totient is φ = 9394592040.
The previous prime is 16440536129. The next prime is 16440536141. The reversal of 16440536133 is 33163504461.
16440536133 is a `hidden beast` number, since 1 + 644 + 0 + 5 + 3 + 6 + 1 + 3 + 3 = 666.
It is not a de Polignac number, because 16440536133 - 22 = 16440536129 is a prime.
It is a super-3 number, since 3×164405361333 (a number of 32 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16440536113) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 130480383 + ... + 130480508.
It is an arithmetic number, because the mean of its divisors is an integer number (2261661064).
Almost surely, 216440536133 is an apocalyptic number.
It is an amenable number.
16440536133 is a deficient number, since it is larger than the sum of its proper divisors (10699396635).
16440536133 is a wasteful number, since it uses less digits than its factorization.
16440536133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260960904 (or 260960901 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 36.
The spelling of 16440536133 in words is "sixteen billion, four hundred forty million, five hundred thirty-six thousand, one hundred thirty-three".
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