Base | Representation |
---|---|
bin | 11110100111111001… |
… | …01101100010111111 |
3 | 1120102210021122222102 |
4 | 33103330231202333 |
5 | 232132321402123 |
6 | 11315223335315 |
7 | 1121263401455 |
oct | 172374554277 |
9 | 46383248872 |
10 | 16440809663 |
11 | 6a77454703 |
12 | 3229bb153b |
13 | 17201b5a55 |
14 | b1d71a9d5 |
15 | 66356b028 |
hex | 3d3f2d8bf |
16440809663 has 2 divisors, whose sum is σ = 16440809664. Its totient is φ = 16440809662.
The previous prime is 16440809647. The next prime is 16440809729. The reversal of 16440809663 is 36690804461.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16440809663 - 24 = 16440809647 is a prime.
It is a super-3 number, since 3×164408096633 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16440809563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8220404831 + 8220404832.
It is an arithmetic number, because the mean of its divisors is an integer number (8220404832).
Almost surely, 216440809663 is an apocalyptic number.
16440809663 is a deficient number, since it is larger than the sum of its proper divisors (1).
16440809663 is an equidigital number, since it uses as much as digits as its factorization.
16440809663 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 746496, while the sum is 47.
The spelling of 16440809663 in words is "sixteen billion, four hundred forty million, eight hundred nine thousand, six hundred sixty-three".
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