Base | Representation |
---|---|
bin | 1110111101000011011111… |
… | …1001011010011111110111 |
3 | 2011012211212022101001010102 |
4 | 3233100313321122133313 |
5 | 4123341331041403321 |
6 | 54545214530144315 |
7 | 3314620613123453 |
oct | 357206771323767 |
9 | 64184768331112 |
10 | 16442072606711 |
11 | 526a053384a14 |
12 | 1a16700a2209b |
13 | 9236333c53bb |
14 | 40bb2ca47663 |
15 | 1d7a69211c0b |
hex | ef437e5a7f7 |
16442072606711 has 2 divisors, whose sum is σ = 16442072606712. Its totient is φ = 16442072606710.
The previous prime is 16442072606669. The next prime is 16442072606753. The reversal of 16442072606711 is 11760627024461.
It is a balanced prime because it is at equal distance from previous prime (16442072606669) and next prime (16442072606753).
It is a cyclic number.
It is not a de Polignac number, because 16442072606711 - 230 = 16440998864887 is a prime.
It is a super-3 number, since 3×164420726067113 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16442072605711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221036303355 + 8221036303356.
It is an arithmetic number, because the mean of its divisors is an integer number (8221036303356).
Almost surely, 216442072606711 is an apocalyptic number.
16442072606711 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442072606711 is an equidigital number, since it uses as much as digits as its factorization.
16442072606711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 677376, while the sum is 47.
The spelling of 16442072606711 in words is "sixteen trillion, four hundred forty-two billion, seventy-two million, six hundred six thousand, seven hundred eleven".
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