Base | Representation |
---|---|
bin | 1110111101000011101110… |
… | …0101100100010010100011 |
3 | 2011012212000121212012022122 |
4 | 3233100323211210102203 |
5 | 4123341442413402203 |
6 | 54545225021054455 |
7 | 3314622264246626 |
oct | 357207345442243 |
9 | 64185017765278 |
10 | 16442134512803 |
11 | 526a08531797a |
12 | 1a167196b742b |
13 | 92364318bb1c |
14 | 40bb36d5ddbd |
15 | 1d7a6e88e538 |
hex | ef43b9644a3 |
16442134512803 has 2 divisors, whose sum is σ = 16442134512804. Its totient is φ = 16442134512802.
The previous prime is 16442134512737. The next prime is 16442134512829. The reversal of 16442134512803 is 30821543124461.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16442134512803 is a prime.
It is a super-3 number, since 3×164421345128033 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (16442134512403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221067256401 + 8221067256402.
It is an arithmetic number, because the mean of its divisors is an integer number (8221067256402).
Almost surely, 216442134512803 is an apocalyptic number.
16442134512803 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442134512803 is an equidigital number, since it uses as much as digits as its factorization.
16442134512803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 552960, while the sum is 44.
The spelling of 16442134512803 in words is "sixteen trillion, four hundred forty-two billion, one hundred thirty-four million, five hundred twelve thousand, eight hundred three".
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