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16442134512737 is a prime number
BaseRepresentation
bin1110111101000011101110…
…0101100100010001100001
32011012212000121212012020012
43233100323211210101201
54123341442413401422
654545225021054305
73314622264246503
oct357207345442141
964185017765205
1016442134512737
11526a08531791a
121a167196b7395
1392364318ba9b
1440bb36d5dd73
151d7a6e88e4e2
hexef43b964461

16442134512737 has 2 divisors, whose sum is σ = 16442134512738. Its totient is φ = 16442134512736.

The previous prime is 16442134512721. The next prime is 16442134512803. The reversal of 16442134512737 is 73721543124461.

It is a happy number.

16442134512737 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15773797197376 + 668337315361 = 3971624^2 + 817519^2 .

It is a cyclic number.

It is not a de Polignac number, because 16442134512737 - 24 = 16442134512721 is a prime.

It is a super-3 number, since 3×164421345127373 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (16442134512707) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221067256368 + 8221067256369.

It is an arithmetic number, because the mean of its divisors is an integer number (8221067256369).

Almost surely, 216442134512737 is an apocalyptic number.

It is an amenable number.

16442134512737 is a deficient number, since it is larger than the sum of its proper divisors (1).

16442134512737 is an equidigital number, since it uses as much as digits as its factorization.

16442134512737 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3386880, while the sum is 50.

The spelling of 16442134512737 in words is "sixteen trillion, four hundred forty-two billion, one hundred thirty-four million, five hundred twelve thousand, seven hundred thirty-seven".