Base | Representation |
---|---|
bin | 11110101000001011… |
… | …11100100011010111 |
3 | 1120102221211122122012 |
4 | 33110011330203113 |
5 | 232133431333143 |
6 | 11315351254435 |
7 | 1121323103204 |
oct | 172405744327 |
9 | 46387748565 |
10 | 16443230423 |
11 | 6a78858434 |
12 | 322a97a41b |
13 | 1720852859 |
14 | b1db8acab |
15 | 663898418 |
hex | 3d417c8d7 |
16443230423 has 2 divisors, whose sum is σ = 16443230424. Its totient is φ = 16443230422.
The previous prime is 16443230411. The next prime is 16443230471. The reversal of 16443230423 is 32403234461.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16443230423 - 210 = 16443229399 is a prime.
It is a super-3 number, since 3×164432304233 (a number of 32 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16443230423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16443230473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221615211 + 8221615212.
It is an arithmetic number, because the mean of its divisors is an integer number (8221615212).
Almost surely, 216443230423 is an apocalyptic number.
16443230423 is a deficient number, since it is larger than the sum of its proper divisors (1).
16443230423 is an equidigital number, since it uses as much as digits as its factorization.
16443230423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 16443230423 its reverse (32403234461), we get a palindrome (48846464884).
The spelling of 16443230423 in words is "sixteen billion, four hundred forty-three million, two hundred thirty thousand, four hundred twenty-three".
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