Base | Representation |
---|---|
bin | 11110101000001011… |
… | …11100100100000111 |
3 | 1120102221211122200222 |
4 | 33110011330210013 |
5 | 232133431333341 |
6 | 11315351254555 |
7 | 1121323103303 |
oct | 172405744407 |
9 | 46387748628 |
10 | 16443230471 |
11 | 6a78858478 |
12 | 322a97a45b |
13 | 1720852895 |
14 | b1db8ad03 |
15 | 66389844b |
hex | 3d417c907 |
16443230471 has 2 divisors, whose sum is σ = 16443230472. Its totient is φ = 16443230470.
The previous prime is 16443230423. The next prime is 16443230473. The reversal of 16443230471 is 17403234461.
16443230471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16443230471 is a prime.
It is a super-3 number, since 3×164432304713 (a number of 32 digits) contains 333 as substring.
Together with 16443230473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16443230473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221615235 + 8221615236.
It is an arithmetic number, because the mean of its divisors is an integer number (8221615236).
Almost surely, 216443230471 is an apocalyptic number.
16443230471 is a deficient number, since it is larger than the sum of its proper divisors (1).
16443230471 is an equidigital number, since it uses as much as digits as its factorization.
16443230471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 16443230471 in words is "sixteen billion, four hundred forty-three million, two hundred thirty thousand, four hundred seventy-one".
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