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16443988202021 is a prime number
BaseRepresentation
bin1110111101001010101000…
…0100110101001000100101
32011020000210210220100212212
43233102222010311020211
54123404241434431041
654550133000053205
73315016233325442
oct357225204651045
964200723810785
1016443988202021
11526a946712036
121a16b56464205
1392387a229553
1440bc712109c9
151d7b2c4a08eb
hexef4aa135225

16443988202021 has 2 divisors, whose sum is σ = 16443988202022. Its totient is φ = 16443988202020.

The previous prime is 16443988202011. The next prime is 16443988202023. The reversal of 16443988202021 is 12020288934461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16124521336225 + 319466865796 = 4015535^2 + 565214^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16443988202021 is a prime.

It is a super-3 number, since 3×164439882020213 (a number of 41 digits) contains 333 as substring.

Together with 16443988202023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16443988202023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221994101010 + 8221994101011.

It is an arithmetic number, because the mean of its divisors is an integer number (8221994101011).

Almost surely, 216443988202021 is an apocalyptic number.

It is an amenable number.

16443988202021 is a deficient number, since it is larger than the sum of its proper divisors (1).

16443988202021 is an equidigital number, since it uses as much as digits as its factorization.

16443988202021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1327104, while the sum is 50.

The spelling of 16443988202021 in words is "sixteen trillion, four hundred forty-three billion, nine hundred eighty-eight million, two hundred two thousand, twenty-one".