164925433 has 4 divisors (see below), whose sum is σ = 172096128. Its totient is φ = 157754740.

The previous prime is 164925419. The next prime is 164925437. The reversal of 164925433 is 334529461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334529461 = 7 ⋅47789923.

It is a cyclic number.

It is not a de Polignac number, because 164925433 - 2⁵ = 164925401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 164925392 and 164925401.

It is not an unprimeable number, because it can be changed into a prime (164925437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3585313 + ... + 3585358.

It is an arithmetic number, because the mean of its divisors is an integer number (43024032).

Almost surely, 2^164925433 is an apocalyptic number.

It is an amenable number.

164925433 is a deficient number, since it is larger than the sum of its proper divisors (7170695).

164925433 is an equidigital number, since it uses as much as digits as its factorization.

164925433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7170694.

The product of its digits is 77760, while the sum is 37.

The square root of 164925433 is about 12842.3297341253. The cubic root of 164925433 is about 548.3980194462.

The spelling of 164925433 in words is "one hundred sixty-four million, nine hundred twenty-five thousand, four hundred thirty-three".