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16493374703 = 131268721131
BaseRepresentation
bin11110101110001010…
…01110110011101111
31120120110012020122202
433113011032303233
5232234300442303
611324342132115
71122502241351
oct172705166357
946513166582
1016493374703
116aa4097593
12324372103b
13172b05b820
14b266c10d1
15667ea0c88
hex3d714ecef

16493374703 has 4 divisors (see below), whose sum is σ = 17762095848. Its totient is φ = 15224653560.

The previous prime is 16493374693. The next prime is 16493374717. The reversal of 16493374703 is 30747339461.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30747339461 = 36238486707.

It is a cyclic number.

It is not a de Polignac number, because 16493374703 - 232 = 12198407407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16493374003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 634360553 + ... + 634360578.

It is an arithmetic number, because the mean of its divisors is an integer number (4440523962).

Almost surely, 216493374703 is an apocalyptic number.

16493374703 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

16493374703 is a deficient number, since it is larger than the sum of its proper divisors (1268721145).

16493374703 is a wasteful number, since it uses less digits than its factorization.

16493374703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1268721144.

The product of its (nonzero) digits is 1143072, while the sum is 47.

The spelling of 16493374703 in words is "sixteen billion, four hundred ninety-three million, three hundred seventy-four thousand, seven hundred three".

Divisors: 1 13 1268721131 16493374703