Base | Representation |
---|---|
bin | 1001100111000101000… |
… | …1110011000110110001 |
3 | 120210011202011212020101 |
4 | 2121301101303012301 |
5 | 10201120431422213 |
6 | 203503344112401 |
7 | 14633363312143 |
oct | 2316121630661 |
9 | 523152155211 |
10 | 165109248433 |
11 | 64027959128 |
12 | 27bba905701 |
13 | 1275392974c |
14 | 7dc42d2c93 |
15 | 44652c3bdd |
hex | 26714731b1 |
165109248433 has 2 divisors, whose sum is σ = 165109248434. Its totient is φ = 165109248432.
The previous prime is 165109248431. The next prime is 165109248439. The reversal of 165109248433 is 334842901561.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 164724774769 + 384473664 = 405863^2 + 19608^2 .
It is a cyclic number.
It is not a de Polignac number, because 165109248433 - 21 = 165109248431 is a prime.
It is a super-2 number, since 2×1651092484332 (a number of 23 digits) contains 22 as substring.
Together with 165109248431, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (165109248431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82554624216 + 82554624217.
It is an arithmetic number, because the mean of its divisors is an integer number (82554624217).
Almost surely, 2165109248433 is an apocalyptic number.
It is an amenable number.
165109248433 is a deficient number, since it is larger than the sum of its proper divisors (1).
165109248433 is an equidigital number, since it uses as much as digits as its factorization.
165109248433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 46.
The spelling of 165109248433 in words is "one hundred sixty-five billion, one hundred nine million, two hundred forty-eight thousand, four hundred thirty-three".
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