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165113133 = 355037711
BaseRepresentation
bin10011101011101…
…10110100101101
3102111200121122020
421311312310231
5314232110013
624214540353
74043303253
oct1165666455
9374617566
10165113133
1185224a39
12473676b9
1328290ba3
1417d005d3
15e767623
hex9d76d2d

165113133 has 4 divisors (see below), whose sum is σ = 220150848. Its totient is φ = 110075420.

The previous prime is 165113131. The next prime is 165113149. The reversal of 165113133 is 331311561.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 165113133 - 21 = 165113131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (165113131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27518853 + ... + 27518858.

It is an arithmetic number, because the mean of its divisors is an integer number (55037712).

Almost surely, 2165113133 is an apocalyptic number.

It is an amenable number.

165113133 is a deficient number, since it is larger than the sum of its proper divisors (55037715).

165113133 is an equidigital number, since it uses as much as digits as its factorization.

165113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55037714.

The product of its digits is 810, while the sum is 24.

The square root of 165113133 is about 12849.6355201227. The cubic root of 165113133 is about 548.6059826886.

Adding to 165113133 its reverse (331311561), we get a palindrome (496424694).

The spelling of 165113133 in words is "one hundred sixty-five million, one hundred thirteen thousand, one hundred thirty-three".

Divisors: 1 3 55037711 165113133