Base | Representation |
---|---|
bin | 1111000010011101100110… |
… | …1000010001000111101111 |
3 | 2011112201200012122121022101 |
4 | 3300213121220101013233 |
5 | 4131402114431142223 |
6 | 55100022021155531 |
7 | 3324420140563312 |
oct | 360473150210757 |
9 | 64481605577271 |
10 | 16534980334063 |
11 | 52a549a372664 |
12 | 1a3070b55bba7 |
13 | 92c31b7626b9 |
14 | 412423bac979 |
15 | 1da1a59a74ad |
hex | f09d9a111ef |
16534980334063 has 2 divisors, whose sum is σ = 16534980334064. Its totient is φ = 16534980334062.
The previous prime is 16534980334021. The next prime is 16534980334091. The reversal of 16534980334063 is 36043308943561.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16534980334063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16534980333995 and 16534980334013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16534980334003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8267490167031 + 8267490167032.
It is an arithmetic number, because the mean of its divisors is an integer number (8267490167032).
Almost surely, 216534980334063 is an apocalyptic number.
16534980334063 is a deficient number, since it is larger than the sum of its proper divisors (1).
16534980334063 is an equidigital number, since it uses as much as digits as its factorization.
16534980334063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16796160, while the sum is 55.
The spelling of 16534980334063 in words is "sixteen trillion, five hundred thirty-four billion, nine hundred eighty million, three hundred thirty-four thousand, sixty-three".
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