Base | Representation |
---|---|
bin | 11000001010010101011… |
… | …111010110110000111001 |
3 | 12212201200201102120212020 |
4 | 120022111133112300321 |
5 | 204200412020314040 |
6 | 3310432240505053 |
7 | 230646255022143 |
oct | 30122537266071 |
9 | 5781621376766 |
10 | 1660365401145 |
11 | 59017aa8a870 |
12 | 22995901b189 |
13 | c075829c509 |
14 | 5a50d8d9c93 |
15 | 2d2cae63cd0 |
hex | 182957d6c39 |
1660365401145 has 32 divisors (see below), whose sum is σ = 2903994906624. Its totient is φ = 803386046400.
The previous prime is 1660365401111. The next prime is 1660365401159. The reversal of 1660365401145 is 5411045630661.
It is not a de Polignac number, because 1660365401145 - 227 = 1660231183417 is a prime.
It is a super-2 number, since 2×16603654011452 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1660365401097 and 1660365401106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10166257 + ... + 10328286.
It is an arithmetic number, because the mean of its divisors is an integer number (90749840832).
Almost surely, 21660365401145 is an apocalyptic number.
1660365401145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1660365401145 is a deficient number, since it is larger than the sum of its proper divisors (1243629505479).
1660365401145 is a wasteful number, since it uses less digits than its factorization.
1660365401145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20495053.
The product of its (nonzero) digits is 259200, while the sum is 42.
The spelling of 1660365401145 in words is "one trillion, six hundred sixty billion, three hundred sixty-five million, four hundred one thousand, one hundred forty-five".
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