1662665401301 has 2 divisors, whose sum is σ = 1662665401302. Its totient is φ = 1662665401300.

The previous prime is 1662665401279. The next prime is 1662665401303. The reversal of 1662665401301 is 1031045662661.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1052081004100 + 610584397201 = 1025710^2 + 781399^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1662665401301 is a prime.

Together with 1662665401303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1662665401303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 831332700650 + 831332700651.

It is an arithmetic number, because the mean of its divisors is an integer number (831332700651).

Almost surely, 2^{1662665401301} is an apocalyptic number.

It is an amenable number.

1662665401301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1662665401301 is an equidigital number, since it uses as much as digits as its factorization.

1662665401301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 1662665401301 in words is "one trillion, six hundred sixty-two billion, six hundred sixty-five million, four hundred one thousand, three hundred one".