Base | Representation |
---|---|
bin | 1001101100001010110… |
… | …1010000001111001001 |
3 | 120220200221211120001122 |
4 | 2123002231100033021 |
5 | 10211420200301022 |
6 | 204251105325025 |
7 | 15012262360544 |
oct | 2330255201711 |
9 | 526627746048 |
10 | 166475400137 |
11 | 64669029122 |
12 | 28320336775 |
13 | 12910986737 |
14 | 80b391385b |
15 | 44e51ce742 |
hex | 26c2b503c9 |
166475400137 has 2 divisors, whose sum is σ = 166475400138. Its totient is φ = 166475400136.
The previous prime is 166475400101. The next prime is 166475400139. The reversal of 166475400137 is 731004574661.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92649619456 + 73825780681 = 304384^2 + 271709^2 .
It is a cyclic number.
It is not a de Polignac number, because 166475400137 - 216 = 166475334601 is a prime.
Together with 166475400139, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (166475400139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83237700068 + 83237700069.
It is an arithmetic number, because the mean of its divisors is an integer number (83237700069).
Almost surely, 2166475400137 is an apocalyptic number.
It is an amenable number.
166475400137 is a deficient number, since it is larger than the sum of its proper divisors (1).
166475400137 is an equidigital number, since it uses as much as digits as its factorization.
166475400137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 423360, while the sum is 44.
Adding to 166475400137 its reverse (731004574661), we get a palindrome (897479974798).
The spelling of 166475400137 in words is "one hundred sixty-six billion, four hundred seventy-five million, four hundred thousand, one hundred thirty-seven".
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