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16672135361741 = 83206320037107
BaseRepresentation
bin1111001010011100100010…
…1101001011010011001101
32012000211200210000220201022
43302213020231023103031
54141124013123033431
655243023453323525
73340344025226546
oct362471055132315
965024623026638
1016672135361741
115348681851a02
121a532084965a5
1393c238aac602
14418d1562b4cd
151dda31a5907b
hexf29c8b4b4cd

16672135361741 has 4 divisors (see below), whose sum is σ = 16672156230912. Its totient is φ = 16672114492572.

The previous prime is 16672135361731. The next prime is 16672135361773. The reversal of 16672135361741 is 14716353127661.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16672135361741 - 218 = 16672135099597 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16672135361731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9186491 + ... + 10850616.

It is an arithmetic number, because the mean of its divisors is an integer number (4168039057728).

Almost surely, 216672135361741 is an apocalyptic number.

It is an amenable number.

16672135361741 is a deficient number, since it is larger than the sum of its proper divisors (20869171).

16672135361741 is an equidigital number, since it uses as much as digits as its factorization.

16672135361741 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20869170.

The product of its digits is 3810240, while the sum is 53.

The spelling of 16672135361741 in words is "sixteen trillion, six hundred seventy-two billion, one hundred thirty-five million, three hundred sixty-one thousand, seven hundred forty-one".

Divisors: 1 832063 20037107 16672135361741