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16915000481 is a prime number
BaseRepresentation
bin11111100000011011…
…00110110010100001
31121122211120001111022
433300031212302201
5234120220003411
611434243055225
71136112063131
oct176015466241
947584501438
1016915000481
1171a0093245
123340971515
131797502532
14b666b4ac1
1568eed6edb
hex3f0366ca1

16915000481 has 2 divisors, whose sum is σ = 16915000482. Its totient is φ = 16915000480.

The previous prime is 16915000451. The next prime is 16915000483. The reversal of 16915000481 is 18400051961.

16915000481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10063299856 + 6851700625 = 100316^2 + 82775^2 .

It is a cyclic number.

It is not a de Polignac number, because 16915000481 - 222 = 16910806177 is a prime.

It is a super-2 number, since 2×169150004812 (a number of 21 digits) contains 22 as substring.

Together with 16915000483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (16915000483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8457500240 + 8457500241.

It is an arithmetic number, because the mean of its divisors is an integer number (8457500241).

Almost surely, 216915000481 is an apocalyptic number.

It is an amenable number.

16915000481 is a deficient number, since it is larger than the sum of its proper divisors (1).

16915000481 is an equidigital number, since it uses as much as digits as its factorization.

16915000481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 35.

The spelling of 16915000481 in words is "sixteen billion, nine hundred fifteen million, four hundred eighty-one", and thus it is an aban number.