Base | Representation |
---|---|
bin | 11000101001000001010… |
… | …011011100100100001000 |
3 | 12222212201212122101021011 |
4 | 120221001103130210020 |
5 | 210220401024401100 |
6 | 3333521440253304 |
7 | 233223603506443 |
oct | 30510123344410 |
9 | 5885655571234 |
10 | 1693312731400 |
11 | 5a314798a724 |
12 | 234213011234 |
13 | c38a91674c4 |
14 | 5bd5755a65a |
15 | 2e0a86cabba |
hex | 18a414dc908 |
1693312731400 has 24 divisors (see below), whose sum is σ = 3936952100970. Its totient is φ = 677325092480.
The previous prime is 1693312731371. The next prime is 1693312731401. The reversal of 1693312731400 is 41372133961.
It can be written as a sum of positive squares in 3 ways, for example, as 1440571256644 + 252741474756 = 1200238^2 + 502734^2 .
It is a Harshad number since it is a multiple of its sum of digits (40).
It is not an unprimeable number, because it can be changed into a prime (1693312731401) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4233281629 + ... + 4233282028.
Almost surely, 21693312731400 is an apocalyptic number.
1693312731400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1693312731400 is an abundant number, since it is smaller than the sum of its proper divisors (2243639369570).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1693312731400 is a wasteful number, since it uses less digits than its factorization.
1693312731400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8466563673 (or 8466563664 counting only the distinct ones).
The product of its (nonzero) digits is 81648, while the sum is 40.
The spelling of 1693312731400 in words is "one trillion, six hundred ninety-three billion, three hundred twelve million, seven hundred thirty-one thousand, four hundred".
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