17000136401 has 2 divisors, whose sum is σ = 17000136402. Its totient is φ = 17000136400.

The previous prime is 17000136389. The next prime is 17000136403. The reversal of 17000136401 is 10463100071.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16997901376 + 2235025 = 130376^2 + 1495^2 .

It is a cyclic number.

It is not a de Polignac number, because 17000136401 - 2²² = 16995942097 is a prime.

Together with 17000136403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (17000136403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8500068200 + 8500068201.

It is an arithmetic number, because the mean of its divisors is an integer number (8500068201).

Almost surely, 2^17000136401 is an apocalyptic number.

It is an amenable number.

17000136401 is a deficient number, since it is larger than the sum of its proper divisors (1).

17000136401 is an equidigital number, since it uses as much as digits as its factorization.

17000136401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 17000136401 its reverse (10463100071), we get a palindrome (27463236472).

The spelling of 17000136401 in words is "seventeen billion, one hundred thirty-six thousand, four hundred one".