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17013119 is a prime number
BaseRepresentation
bin100000011100…
…1100101111111
31012000100121112
41000321211333
513323404434
61404352235
7264415634
oct100714577
935010545
1017013119
119670232
12584567b
1336a8a46
14238c18b
151760dce
hex103997f

17013119 has 2 divisors, whose sum is σ = 17013120. Its totient is φ = 17013118.

The previous prime is 17013103. The next prime is 17013127. The reversal of 17013119 is 91131071.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 17013119 - 24 = 17013103 is a prime.

It is a super-2 number, since 2×170131192 = 578892436216322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 17013094 and 17013103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17013149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8506559 + 8506560.

It is an arithmetic number, because the mean of its divisors is an integer number (8506560).

Almost surely, 217013119 is an apocalyptic number.

17013119 is a deficient number, since it is larger than the sum of its proper divisors (1).

17013119 is an equidigital number, since it uses as much as digits as its factorization.

17013119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 189, while the sum is 23.

The square root of 17013119 is about 4124.6962312393. The cubic root of 17013119 is about 257.1942844966.

The spelling of 17013119 in words is "seventeen million, thirteen thousand, one hundred nineteen".