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17042103121 = 166191025459
BaseRepresentation
bin11111101111100100…
…11101101101010001
31121222200201112112111
433313302131231101
5234400234244441
611455023225321
71142214325561
oct176762355521
947880645474
1017042103121
11725590634a
123377448241
1317b79452b4
14b7951cda1
1569b242081
hex3f7c9db51

17042103121 has 4 divisors (see below), whose sum is σ = 17043145200. Its totient is φ = 17041061044.

The previous prime is 17042103077. The next prime is 17042103131. The reversal of 17042103121 is 12130124071.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 17042103121 - 211 = 17042101073 is a prime.

It is a super-3 number, since 3×170421031213 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 17042103092 and 17042103101.

It is not an unprimeable number, because it can be changed into a prime (17042103131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 496111 + ... + 529348.

It is an arithmetic number, because the mean of its divisors is an integer number (4260786300).

Almost surely, 217042103121 is an apocalyptic number.

It is an amenable number.

17042103121 is a deficient number, since it is larger than the sum of its proper divisors (1042079).

17042103121 is a wasteful number, since it uses less digits than its factorization.

17042103121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1042078.

The product of its (nonzero) digits is 336, while the sum is 22.

Adding to 17042103121 its reverse (12130124071), we get a palindrome (29172227192).

The spelling of 17042103121 in words is "seventeen billion, forty-two million, one hundred three thousand, one hundred twenty-one".

Divisors: 1 16619 1025459 17042103121