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17055984613 is a prime number
BaseRepresentation
bin11111110001001110…
…11010101111100101
31122000122211210100211
433320213122233211
5234412313001423
611500240535421
71142443322443
oct177047325745
948018753324
1017055984613
117262727758
123380021571
1317ba7957b5
14b7b2d3b93
1569c58510d
hex3f89dabe5

17055984613 has 2 divisors, whose sum is σ = 17055984614. Its totient is φ = 17055984612.

The previous prime is 17055984611. The next prime is 17055984623. The reversal of 17055984613 is 31648955071.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15649509604 + 1406475009 = 125098^2 + 37503^2 .

It is an emirp because it is prime and its reverse (31648955071) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 17055984613 - 21 = 17055984611 is a prime.

It is a super-2 number, since 2×170559846132 (a number of 21 digits) contains 22 as substring.

Together with 17055984611, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17055984611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8527992306 + 8527992307.

It is an arithmetic number, because the mean of its divisors is an integer number (8527992307).

Almost surely, 217055984613 is an apocalyptic number.

It is an amenable number.

17055984613 is a deficient number, since it is larger than the sum of its proper divisors (1).

17055984613 is an equidigital number, since it uses as much as digits as its factorization.

17055984613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 907200, while the sum is 49.

The spelling of 17055984613 in words is "seventeen billion, fifty-five million, nine hundred eighty-four thousand, six hundred thirteen".