Base | Representation |
---|---|
bin | 11000111001110010001… |
… | …001111111010011111111 |
3 | 20001121012021211101021120 |
4 | 120321302021333103333 |
5 | 211014231411030210 |
6 | 3350055503402023 |
7 | 234431624510145 |
oct | 30716211772377 |
9 | 6047167741246 |
10 | 1711312205055 |
11 | 5aa844142692 |
12 | 2377b6bb3313 |
13 | c54b724232b |
14 | 5cb83c8b595 |
15 | 2e7ad9cd270 |
hex | 18e7227f4ff |
1711312205055 has 8 divisors (see below), whose sum is σ = 2738099528112. Its totient is φ = 912699842688.
The previous prime is 1711312204997. The next prime is 1711312205087. The reversal of 1711312205055 is 5505022131171.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1711312205055 - 217 = 1711312073983 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57043740154 + ... + 57043740183.
It is an arithmetic number, because the mean of its divisors is an integer number (342262441014).
Almost surely, 21711312205055 is an apocalyptic number.
1711312205055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1711312205055 is a deficient number, since it is larger than the sum of its proper divisors (1026787323057).
1711312205055 is a wasteful number, since it uses less digits than its factorization.
1711312205055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114087480345.
The product of its (nonzero) digits is 10500, while the sum is 33.
The spelling of 1711312205055 in words is "one trillion, seven hundred eleven billion, three hundred twelve million, two hundred five thousand, fifty-five".
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