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1712042313469 is a prime number
BaseRepresentation
bin11000111010011101101…
…011001000011011111101
320001200002011122201201221
4120322131223020123331
5211022230313012334
63350300144233341
7234456001361125
oct30723553103375
96050064581657
101712042313469
11600089286974
1223797b60b851
13c55a2593b47
145cc12c21c85
152e802b4b8b4
hex18e9dac86fd

1712042313469 has 2 divisors, whose sum is σ = 1712042313470. Its totient is φ = 1712042313468.

The previous prime is 1712042313467. The next prime is 1712042313479. The reversal of 1712042313469 is 9643132402171.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 932794750969 + 779247562500 = 965813^2 + 882750^2 .

It is a cyclic number.

It is not a de Polignac number, because 1712042313469 - 21 = 1712042313467 is a prime.

It is a super-2 number, since 2×17120423134692 (a number of 25 digits) contains 22 as substring.

Together with 1712042313467, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1712042313467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 856021156734 + 856021156735.

It is an arithmetic number, because the mean of its divisors is an integer number (856021156735).

Almost surely, 21712042313469 is an apocalyptic number.

It is an amenable number.

1712042313469 is a deficient number, since it is larger than the sum of its proper divisors (1).

1712042313469 is an equidigital number, since it uses as much as digits as its factorization.

1712042313469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 1712042313469 in words is "one trillion, seven hundred twelve billion, forty-two million, three hundred thirteen thousand, four hundred sixty-nine".