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17121113 = 47675437
BaseRepresentation
bin100000101001…
…1111101011001
31012012211202022
41001103331121
513340333423
61410544225
7265345532
oct101237531
935184668
1017121113
119734389
125898075
133715c49
1423b9689
151782dc8
hex1053f59

17121113 has 8 divisors (see below), whose sum is σ = 17749632. Its totient is φ = 16503696.

The previous prime is 17121103. The next prime is 17121119. The reversal of 17121113 is 31112171.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 17121113 - 212 = 17117017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 17121091 and 17121100.

It is not an unprimeable number, because it can be changed into a prime (17121119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 431 + ... + 5867.

It is an arithmetic number, because the mean of its divisors is an integer number (2218704).

Almost surely, 217121113 is an apocalyptic number.

It is an amenable number.

17121113 is a deficient number, since it is larger than the sum of its proper divisors (628519).

17121113 is an equidigital number, since it uses as much as digits as its factorization.

17121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5551.

The product of its digits is 42, while the sum is 17.

The square root of 17121113 is about 4137.7666681436. The cubic root of 17121113 is about 257.7373335789.

Adding to 17121113 its reverse (31112171), we get a palindrome (48233284).

The spelling of 17121113 in words is "seventeen million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 47 67 3149 5437 255539 364279 17121113