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171225883760341 is a prime number
BaseRepresentation
bin100110111011101010100001…
…111110100101011011010101
3211110021000221020111200011011
4212323222201332211123111
5134420331102220312331
61404100030213412221
751031443006633424
oct4673524176453325
9743230836450134
10171225883760341
114a615542595663
121725488203a071
1374706baa9c867
14303d53c6792bb
1514bdea15433b1
hex9bbaa1fa56d5

171225883760341 has 2 divisors, whose sum is σ = 171225883760342. Its totient is φ = 171225883760340.

The previous prime is 171225883760339. The next prime is 171225883760377. The reversal of 171225883760341 is 143067388522171.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114844872564900 + 56381011195441 = 10716570^2 + 7508729^2 .

It is a cyclic number.

It is not a de Polignac number, because 171225883760341 - 21 = 171225883760339 is a prime.

Together with 171225883760339, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171225883760381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85612941880170 + 85612941880171.

It is an arithmetic number, because the mean of its divisors is an integer number (85612941880171).

Almost surely, 2171225883760341 is an apocalyptic number.

It is an amenable number.

171225883760341 is a deficient number, since it is larger than the sum of its proper divisors (1).

171225883760341 is an equidigital number, since it uses as much as digits as its factorization.

171225883760341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13547520, while the sum is 58.

The spelling of 171225883760341 in words is "one hundred seventy-one trillion, two hundred twenty-five billion, eight hundred eighty-three million, seven hundred sixty thousand, three hundred forty-one".