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171283525382141 is a prime number
BaseRepresentation
bin100110111100100000001101…
…101011111010111111111101
3211110110112201101101110012122
4212330200031223322333331
5134422302124444212031
61404142322033412325
751035553301426064
oct4674401553727775
9743415641343178
10171283525382141
114a637a317a9227
1217263a8a10a0a5
137475c75a54b93
143042249c251db
1514c0726be247b
hex9bc80dafaffd

171283525382141 has 2 divisors, whose sum is σ = 171283525382142. Its totient is φ = 171283525382140.

The previous prime is 171283525382087. The next prime is 171283525382143. The reversal of 171283525382141 is 141283525382171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 166537863552025 + 4745661830116 = 12904955^2 + 2178454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-171283525382141 is a prime.

It is a Sophie Germain prime.

Together with 171283525382143, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171283525382143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85641762691070 + 85641762691071.

It is an arithmetic number, because the mean of its divisors is an integer number (85641762691071).

Almost surely, 2171283525382141 is an apocalyptic number.

It is an amenable number.

171283525382141 is a deficient number, since it is larger than the sum of its proper divisors (1).

171283525382141 is an equidigital number, since it uses as much as digits as its factorization.

171283525382141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3225600, while the sum is 53.

The spelling of 171283525382141 in words is "one hundred seventy-one trillion, two hundred eighty-three billion, five hundred twenty-five million, three hundred eighty-two thousand, one hundred forty-one".