Base | Representation |
---|---|
bin | 11111111011110101… |
… | …11111000100111101 |
3 | 1122020212100020212101 |
4 | 33331322333010331 |
5 | 240103110002003 |
6 | 11513140505101 |
7 | 1144604045323 |
oct | 177572770475 |
9 | 48225306771 |
10 | 17145000253 |
11 | 72a89a64a7 |
12 | 33a59ab191 |
13 | 1803061684 |
14 | b89065d13 |
15 | 6a52ba11d |
hex | 3fdebf13d |
17145000253 has 2 divisors, whose sum is σ = 17145000254. Its totient is φ = 17145000252.
The previous prime is 17145000247. The next prime is 17145000277. The reversal of 17145000253 is 35200054171.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15891627844 + 1253372409 = 126062^2 + 35403^2 .
It is a cyclic number.
It is not a de Polignac number, because 17145000253 - 25 = 17145000221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17145000203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8572500126 + 8572500127.
It is an arithmetic number, because the mean of its divisors is an integer number (8572500127).
Almost surely, 217145000253 is an apocalyptic number.
It is an amenable number.
17145000253 is a deficient number, since it is larger than the sum of its proper divisors (1).
17145000253 is an equidigital number, since it uses as much as digits as its factorization.
17145000253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4200, while the sum is 28.
The spelling of 17145000253 in words is "seventeen billion, one hundred forty-five million, two hundred fifty-three", and thus it is an aban number.
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