Base | Representation |
---|---|
bin | 1010000001001010110… |
… | …0000111111000010011 |
3 | 121110020210120010010021 |
4 | 2200102230013320103 |
5 | 10304441213421324 |
6 | 211022310444311 |
7 | 15302046654403 |
oct | 2402254077023 |
9 | 543223503107 |
10 | 172112248339 |
11 | 66aa0971659 |
12 | 29434063697 |
13 | 132cb742c85 |
14 | 848a3d0803 |
15 | 4724ed1ae4 |
hex | 2812b07e13 |
172112248339 has 2 divisors, whose sum is σ = 172112248340. Its totient is φ = 172112248338.
The previous prime is 172112248337. The next prime is 172112248433. The reversal of 172112248339 is 933842211271.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 172112248339 - 21 = 172112248337 is a prime.
Together with 172112248337, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 172112248295 and 172112248304.
It is not a weakly prime, because it can be changed into another prime (172112248333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86056124169 + 86056124170.
It is an arithmetic number, because the mean of its divisors is an integer number (86056124170).
Almost surely, 2172112248339 is an apocalyptic number.
172112248339 is a deficient number, since it is larger than the sum of its proper divisors (1).
172112248339 is an equidigital number, since it uses as much as digits as its factorization.
172112248339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 145152, while the sum is 43.
The spelling of 172112248339 in words is "one hundred seventy-two billion, one hundred twelve million, two hundred forty-eight thousand, three hundred thirty-nine".
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