Base | Representation |
---|---|
bin | 1010000001001010110… |
… | …0000111111001110001 |
3 | 121110020210120010020202 |
4 | 2200102230013321301 |
5 | 10304441213422213 |
6 | 211022310444545 |
7 | 15302046654566 |
oct | 2402254077161 |
9 | 543223503222 |
10 | 172112248433 |
11 | 66aa0971734 |
12 | 29434063755 |
13 | 132cb743028 |
14 | 848a3d086d |
15 | 4724ed1b58 |
hex | 2812b07e71 |
172112248433 has 2 divisors, whose sum is σ = 172112248434. Its totient is φ = 172112248432.
The previous prime is 172112248339. The next prime is 172112248513. The reversal of 172112248433 is 334842211271.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 137035453489 + 35076794944 = 370183^2 + 187288^2 .
It is a cyclic number.
It is not a de Polignac number, because 172112248433 - 218 = 172111986289 is a prime.
It is not a weakly prime, because it can be changed into another prime (172112248333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86056124216 + 86056124217.
It is an arithmetic number, because the mean of its divisors is an integer number (86056124217).
Almost surely, 2172112248433 is an apocalyptic number.
It is an amenable number.
172112248433 is a deficient number, since it is larger than the sum of its proper divisors (1).
172112248433 is an equidigital number, since it uses as much as digits as its factorization.
172112248433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 64512, while the sum is 38.
The spelling of 172112248433 in words is "one hundred seventy-two billion, one hundred twelve million, two hundred forty-eight thousand, four hundred thirty-three".
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