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172131083333 = 1115648280303
BaseRepresentation
bin1010000001001111001…
…1111110010001000101
3121110022010000000212122
42200103303332101011
510310011024131313
6211024222255325
715302366032046
oct2402363762105
9543263000778
10172131083333
1167000566670
122943a427545
1313302609041
14848cad48cd
1547269a2708
hex2813cfe445

172131083333 has 4 divisors (see below), whose sum is σ = 187779363648. Its totient is φ = 156482803020.

The previous prime is 172131083329. The next prime is 172131083363. The reversal of 172131083333 is 333380131271.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 172131083333 - 22 = 172131083329 is a prime.

It is a super-5 number, since 5×1721310833335 (a number of 57 digits) contains 55555 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 172131083293 and 172131083302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (172131083363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7824140141 + ... + 7824140162.

It is an arithmetic number, because the mean of its divisors is an integer number (46944840912).

Almost surely, 2172131083333 is an apocalyptic number.

It is an amenable number.

172131083333 is a deficient number, since it is larger than the sum of its proper divisors (15648280315).

172131083333 is a wasteful number, since it uses less digits than its factorization.

172131083333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15648280314.

The product of its (nonzero) digits is 27216, while the sum is 35.

The spelling of 172131083333 in words is "one hundred seventy-two billion, one hundred thirty-one million, eighty-three thousand, three hundred thirty-three".

Divisors: 1 11 15648280303 172131083333