Base | Representation |
---|---|
bin | 1010000001010000001… |
… | …0000101110000110110 |
3 | 121110022100222001022101 |
4 | 2200110002011300312 |
5 | 10310013001042204 |
6 | 211024433452314 |
7 | 15302442344242 |
oct | 2402402056066 |
9 | 543270861271 |
10 | 172134784054 |
11 | 67002664012 |
12 | 2943b71109a |
13 | 1330330360c |
14 | 848d3b9422 |
15 | 4726e83ea4 |
hex | 2814085c36 |
172134784054 has 4 divisors (see below), whose sum is σ = 258202176084. Its totient is φ = 86067392026.
The previous prime is 172134784037. The next prime is 172134784099. The reversal of 172134784054 is 450487431271.
172134784054 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 172134783995 and 172134784013.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43033696012 + ... + 43033696015.
It is an arithmetic number, because the mean of its divisors is an integer number (64550544021).
Almost surely, 2172134784054 is an apocalyptic number.
172134784054 is a deficient number, since it is larger than the sum of its proper divisors (86067392030).
172134784054 is an equidigital number, since it uses as much as digits as its factorization.
172134784054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86067392029.
The product of its (nonzero) digits is 752640, while the sum is 46.
The spelling of 172134784054 in words is "one hundred seventy-two billion, one hundred thirty-four million, seven hundred eighty-four thousand, fifty-four".
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