Base | Representation |
---|---|
bin | 10000000101101100… |
… | …101111011111010101 |
3 | 1122120221212112002002 |
4 | 100011230233133111 |
5 | 240340010442432 |
6 | 11534121325045 |
7 | 1151050122623 |
oct | 200554573725 |
9 | 48527775062 |
10 | 17275484117 |
11 | 7365618a01 |
12 | 3421636785 |
13 | 18240b9468 |
14 | b9c510513 |
15 | 6b1991e62 |
hex | 405b2f7d5 |
17275484117 has 2 divisors, whose sum is σ = 17275484118. Its totient is φ = 17275484116.
The previous prime is 17275484101. The next prime is 17275484119. The reversal of 17275484117 is 71148457271.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11969672836 + 5305811281 = 109406^2 + 72841^2 .
It is a cyclic number.
It is not a de Polignac number, because 17275484117 - 24 = 17275484101 is a prime.
Together with 17275484119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17275484119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8637742058 + 8637742059.
It is an arithmetic number, because the mean of its divisors is an integer number (8637742059).
Almost surely, 217275484117 is an apocalyptic number.
It is an amenable number.
17275484117 is a deficient number, since it is larger than the sum of its proper divisors (1).
17275484117 is an equidigital number, since it uses as much as digits as its factorization.
17275484117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 439040, while the sum is 47.
The spelling of 17275484117 in words is "seventeen billion, two hundred seventy-five million, four hundred eighty-four thousand, one hundred seventeen".
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