Base | Representation |
---|---|
bin | 11001001010001000011… |
… | …000111111000111010111 |
3 | 20010021111120201001102121 |
4 | 121022020120333013113 |
5 | 211311203431314333 |
6 | 3402121335120411 |
7 | 235622613626506 |
oct | 31121030770727 |
9 | 6107446631377 |
10 | 1728865104343 |
11 | 607231309723 |
12 | 23b095513107 |
13 | c705394c780 |
14 | 5d96b17283d |
15 | 2ee899bc32d |
hex | 1928863f1d7 |
1728865104343 has 4 divisors (see below), whose sum is σ = 1861854727768. Its totient is φ = 1595875480920.
The previous prime is 1728865104319. The next prime is 1728865104347. The reversal of 1728865104343 is 3434015688271.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1728865104343 - 29 = 1728865103831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1728865104347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66494811693 + ... + 66494811718.
It is an arithmetic number, because the mean of its divisors is an integer number (465463681942).
Almost surely, 21728865104343 is an apocalyptic number.
1728865104343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1728865104343 is a deficient number, since it is larger than the sum of its proper divisors (132989623425).
1728865104343 is a wasteful number, since it uses less digits than its factorization.
1728865104343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 132989623424.
The product of its (nonzero) digits is 3870720, while the sum is 52.
The spelling of 1728865104343 in words is "one trillion, seven hundred twenty-eight billion, eight hundred sixty-five million, one hundred four thousand, three hundred forty-three".
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