17401313 has 2 divisors, whose sum is σ = 17401314. Its totient is φ = 17401312.

The previous prime is 17401301. The next prime is 17401333. The reversal of 17401313 is 31310471.

It is a happy number.

It is an a-pointer prime, because the next prime (17401333) can be obtained adding 17401313 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11751184 + 5650129 = 3428^2 + 2377^2 .

It is an emirp because it is prime and its reverse (31310471) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 17401313 - 2⁴ = 17401297 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (17401333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8700656 + 8700657.

It is an arithmetic number, because the mean of its divisors is an integer number (8700657).

Almost surely, 2^17401313 is an apocalyptic number.

It is an amenable number.

17401313 is a deficient number, since it is larger than the sum of its proper divisors (1).

17401313 is an equidigital number, since it uses as much as digits as its factorization.

17401313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

The square root of 17401313 is about 4171.4881037826. The cubic root of 17401313 is about 259.1357546742.

Adding to 17401313 its reverse (31310471), we get a palindrome (48711784).

The spelling of 17401313 in words is "seventeen million, four hundred one thousand, three hundred thirteen".